No abstract

The title compound 1-N-(3-pyridylmethyl)aminonaphthalene hydrochloride (C16H15N2Cl) was obtained by a reaction of α-naphthylamine (1) and N-pyridincarboxaldehyde (2) in anhydrous ethanol in the first step. The formed imine (3) was reduced with sodium borohydride in anhydrous methanol to give the product 1-N-(3-pyridylmethyl)aminonaphthalene (4). Finally, the hydrochloride was prepared by addition of a hydrochloric acid–ethyl acetate solution (ratio 1:3) with constant stirring and maintaining the temperature between 0 and 5 °C, obtaining a yellow polycrystalline solid corresponding to the respective derivative (5). The X-ray powder diffraction pattern for the new compound (5) was obtained. The compound (5) crystallizes in a monoclinic system with the space group P21/m (No. 11) and refined unit-cell parameters: a = 16.257 (8) Å, b = 9.236 (7) Å, c = 13.221 (6) Å, β = 94.87° (5), Z = 6, and V = 1978 (1) Å3.