Neither free halogen nor halogenite has to be used for the haloform reaction if it is carried out electrocatalytically. Reduction of 1 (R = Ph, 1‐naphthyl, Me(CH2)5, iPr, PhCHCH) in MeOH in the presence of NaBr at 30 °C and a constant current density of 220 mA cm−2 suffices in order to obtain the methyl ester 2 in 61–68% yield. Under the same conditions ketones such as PhCOEt afford α‐hydroxyacetals, in the case of 1, R = PhCH2, on the other hand, predominantly the Favorski rearrangement product methyl 3‐phenylpropionate is formed.

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