1977
DOI: 10.3891/acta.chem.scand.31b-0088
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Anodic Oxidation of Benzenesulfinate Ion.

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Cited by 25 publications
(20 citation statements)
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“…Upon visible light irradiation, single electron transfer (SET) from the sodium sulfinate salt (for PhSO 2 . /PhSO 2 Na, E 1/2 red = +0.5 V vs. SCE in MeCN) to the highly oxidizing excited state B of the photocatalyst (PC) would generate the sulfonyl free radical (PhSO 2 . ) along with the reduced form C of the photocatalyst.…”
Section: Introductionsupporting
confidence: 72%
“…Upon visible light irradiation, single electron transfer (SET) from the sodium sulfinate salt (for PhSO 2 . /PhSO 2 Na, E 1/2 red = +0.5 V vs. SCE in MeCN) to the highly oxidizing excited state B of the photocatalyst (PC) would generate the sulfonyl free radical (PhSO 2 . ) along with the reduced form C of the photocatalyst.…”
Section: Introductionsupporting
confidence: 72%
“…10 6 m –1 s –1 ), and must be followed by a radical fragmentation to obtain the desired alkene. In the same event is produced the stabilized phenyl sulfonyl radical, which is easily reduced [ E 1/2 (PhSO 2 · /PhSO 2 – ) = +0.50 V vs. SCE] by the hydroflavin radical [ E 1/2 (RFTA/RFTAH · ) ≈ –0.60 V vs. SCE], thereby closing the catalytic cycle after proton transfer. According to the redox potentials involved, this electron transfer is highly exergonic (ΔG ET ca.…”
Section: Resultsmentioning
confidence: 99%
“…Reaction of 5 with a vinyl sulfone would then generate the β-sulfonyl radical 6 , which after elimination of a sulfinyl radical would provide the allylic amine product. Completion of the photocatalytic cycle would then be accomplished via reduction of the sulfinyl radical (For PhSO 2 • /PhSO 2 Na, E 1/2 red = +0.50 V vs SCE) 19 with Ir II 7 ( E 1/2 [Ir III/II ] = −1.37 V vs SCE) 17 to give a sulfinate anion while reconstituting the photocatalyst 1 .…”
mentioning
confidence: 99%