1982
DOI: 10.1007/bfb0071282
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Droites en position generale dans l'espace projectif

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Cited by 78 publications
(109 citation statements)
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“…We have the following triples (d, a, ψ): (16, 1, 3), (15,2,6), (15,3,2), (14,4,5), (14,5, 2) and we exclude the triples (15,2,6) and (14,4,5) which have ψ > 3. We have the following quintuples (d, a, ψ, w, u): (16,1,3,5,4), (15,3,2,4,1), (14,5,2,3,2) for which Claim 4 holds. Now assume k = 6 and hence 1 ≤ a ≤ 4.…”
Section: ([17]) Hence It Is Sufficient To Prove Thatmentioning
confidence: 99%
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“…We have the following triples (d, a, ψ): (16, 1, 3), (15,2,6), (15,3,2), (14,4,5), (14,5, 2) and we exclude the triples (15,2,6) and (14,4,5) which have ψ > 3. We have the following quintuples (d, a, ψ, w, u): (16,1,3,5,4), (15,3,2,4,1), (14,5,2,3,2) for which Claim 4 holds. Now assume k = 6 and hence 1 ≤ a ≤ 4.…”
Section: ([17]) Hence It Is Sufficient To Prove Thatmentioning
confidence: 99%
“…Since the case a = 0 is true by [16], we may assume 0 ≤ φ ≤ 3. The case φ = 0, by step (a) (it is the case ψ = 0.…”
Section: ([17]) Hence It Is Sufficient To Prove Thatmentioning
confidence: 99%
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“…Hence W (r, t, a) is parametrized by an irreducible variety. Hence (as in [14] for the case a = 0) it makes sense to compute the Hilbert function of a general element of W (r, t, a). In this paper we prove the following result Theorem 1.…”
Section: Introductionmentioning
confidence: 99%