“…The pixels in ascending order is {110, 110, 113, 113}, P E min = P E max = 0. The numbers of secret bits for x σ (1) and x σ (4) are 0 , 3 respectively by (13), and the first two secret messages bit are (0) 2 and (101) 2 ; we determine that 1, 3 are position number α for x σ (1) and x σ (4) according to (14); x σ (1) , x σ (1) , x σ (4) and x σ (4) are then substituted into (12) and (11) to obtain the marked pixels x σ (1) = x σ (1) − 1/2 = 110, x σ (1) = x σ (1) = 110, x σ (4) = x σ (4) = 113, x σ (4) = x σ (4) + 3/2 = 114. Write the stego pixels x σ (1) , x σ (1) , x σ (4) , x σ (4) to corresponding original position, and then obtain two stego blocks X 1 : {110, 113, 110, 113} and X 1 : {110, 113, 110, 114}.…”