2000
DOI: 10.1006/jdeq.1999.3684
|View full text |Cite
|
Sign up to set email alerts
|

Estimates for the Hill Operator, I

Evgeni Korotyaev
Help me understand this report

Search citation statements

Order By: Relevance

Paper Sections

Select...
1
1

Citation Types

0
28
0

Year Published

2000
2000
2021
2021

Publication Types

Select...
6
1

Relationship

3
4

Authors

Journals

citations
Cited by 37 publications
(28 citation statements)
references
References 14 publications
0
28
0
Order By: Relevance
“…Thus, the mapping k (and, therefore, h) allows to recover the sequences {z ± n }, {m n } from {h n } and inversely {h n } from {z ± n }, {m n }. In addition, the quasimomentum k is crucial to derive the double-sided estimates in assertion i) (see [22], [27], [29]). …”
Section: Theorem 2 I) the Mappingsmentioning
confidence: 99%
See 1 more Smart Citation
“…Thus, the mapping k (and, therefore, h) allows to recover the sequences {z ± n }, {m n } from {h n } and inversely {h n } from {z ± n }, {m n }. In addition, the quasimomentum k is crucial to derive the double-sided estimates in assertion i) (see [22], [27], [29]). …”
Section: Theorem 2 I) the Mappingsmentioning
confidence: 99%
“…Two-sided estimates for various parameters of the Hill operator (the norm of a periodic potential, effective masses, gap lengths, height of slits |h n | etc.) were obtained in [27,28,29]. The results for the Hill operator [34,35], [23,24] were extended in [25] to the case of singular potentials V with V ∈ L 2 (T).…”
Section: Theorem 4 the Following Identities Are Fulfilledmentioning
confidence: 99%
“…Then we should study the metric properties of a conformal mapping from C + onto a "comb" K + (h). A similar analysis was done partially in [11][12][13][14][15][16]. In the present paper we use an approach, based on the identities for the Dirichlet integral (1.2) from [11] and the estimates from Theorem 2.8 and Lemma 3.1.…”
mentioning
confidence: 90%
“…Remark that Korotyaev obtained the two-sided estimates for the 2 ω -norms, where ω n = 1 + (2πn) 2m , m 0, for the even case h −n = h n , n ∈ Z [15][16][17], and for 2 1 -norms without symmetry [14,19] (in all these estimates the factor c 0 = e h ∞ /π is absent).…”
mentioning
confidence: 98%
See 1 more Smart Citation