2023
DOI: 10.1016/j.disc.2022.113193
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Four proofs of the directed Brooks' Theorem

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Cited by 4 publications
(5 citation statements)
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“…Similarly, it is well known (see Lemma 12(1)) that every vertex in a k-dicritical digraph has degree at least 2(k −1) and hence a k-dicritical digraph has at least (k −1)|V (G)| arcs. Brooks' theorem was generalised in [Moh10] (see also [AA22]) to digraphs, and implies a simple characterisation of the k-dicritical digraphs G with exactly (k − 1)|V (G)| arcs. For G a digraph, let ∆ max (G) be the maximum over the vertices of G of the maximum of their in-degree and their out-degree.…”
Section: Introduction and Resultsmentioning
confidence: 99%
“…Similarly, it is well known (see Lemma 12(1)) that every vertex in a k-dicritical digraph has degree at least 2(k −1) and hence a k-dicritical digraph has at least (k −1)|V (G)| arcs. Brooks' theorem was generalised in [Moh10] (see also [AA22]) to digraphs, and implies a simple characterisation of the k-dicritical digraphs G with exactly (k − 1)|V (G)| arcs. For G a digraph, let ∆ max (G) be the maximum over the vertices of G of the maximum of their in-degree and their out-degree.…”
Section: Introduction and Resultsmentioning
confidence: 99%
“…The directed version of Brooks' theorem was first proved by Harutyunyan and Mohar in [13]. Aboulker and Aubian gave four new proofs of the following theorem in [1]. .…”
Section: Digraph Colouringmentioning
confidence: 99%
“…. Unfortunately, Aboulker and Aubian [1] proved that, given a digraph D, deciding whether D is D Δ ( ) min -dicolourable is NP-complete. Thus, unless P = NP, we cannot expect an easy characterization of digraphs satisfying…”
Section: Digraph Colouringmentioning
confidence: 99%
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