“…Ferrous P460 of H A 0 will reduce 0, [12]; thus c hemes of the enzyme may serve as a steady-state 'pool' of reductant for 0, activation by heme P460. HAO-P460 reduces H,O, at rates high enough to account for the rate of oxygen activation for nitrite synthesis during turnover of H A 0 (and H A 0 activity can account for the rate of nitrite production by intact cells [3]). The turnover of HAO, 120mol NH,OH s-' mol P-460-', would require the one-electron activation of dioxygen at a rate of 120 rnol s -' rnol P460-I (NH,OH+Fe"'+'/, 0, 4 HNO, …”