“…. By combining the results in (77), (78), (79) and (80), the total BER for the third user can be computed as 4,11,13,14,15,16,17,18] , Similar to the N = 2 NOMA system, the average BER of N = 3 NOMA system can be evaluated by averaging over the PDFs of all γ n,c values, which are given in Appendix I. Therefore, by substituting N = 3 and n = [1,2,3] in the ordered PDF in (93), the exact average BER of the first and second users can be simplified tō 4, 11, 13, 14, 15, 16, 17, 18} ,…”