We have recorded the resonance-enhanced multiphoton ionization
spectrum for NO (A) products from photodissociation of the N2-NO complex. We made measurements at excitation energies ranging
from 28 to 758 cm–1 above the threshold to produce
NO (A) + N2 (X) products, and the resulting spectra reveal
the NO (A) rotational states formed during dissociation, allowing
us to determine the rotational state distribution. At the lowest available
energies, 28 and 50 cm–1 above threshold, we observed
contributions from NO (A) rotational states that exceed the available
energy and must originate from excitation due to hotbands of the complex.
At all higher energies, we did not observe any energetically disallowed
NO (A) rotational states, and for all available energies above 259
cm–1 the observed rotational transitions do not
extend to the maximum allowed by energy conservation. Furthermore,
the observed distributions were typically biased toward low rotational
states, in contrast with expectations from vibrational predissociation.
From the rotational state distributions, we determined the average
fraction of energy partitioned into NO (A) rotation, f
NO rot, ave, to be 0.088 at the highest available
energy, and this fraction increased as the available energy decreased.
By combining the average NO (A) rotational energy along with the average
center-of-mass translational energy from our previous work, we determined
the average rotational energy for the undetected N2 (X)
photoproduct. The results showed that the N2 fragment has
a higher average rotational energy relative to the NO fragment. Finally,
we found that the NO (A) rotational state distribution was colder
than expected for a statistical dissociation.