Supersymmetric black rings and three-charge supertubes

Abstract

We present supergravity solutions for 1/8-supersymmetric black supertubes with three charges and three dipoles. Their reduction to five dimensions yields supersymmetric black rings with regular horizons and two independent angular momenta. The general solution contains seven independent parameters and provides the first example of non-uniqueness of supersymmetric black holes. In ten dimensions, the solutions can be realized as D1-D5-P black supertubes. We also present a worldvolume construction of a supertube that exhibits three dipoles explicitly. This description allows an arbitrary cross-section but captures only one of the angular momenta.

One ring to rule them all and in the darkness bind them?

“…We would, however note that if we want to describe a bound state then it seems reasonable to assume that all of the branes must be sourced along the same profile. We will also see that near the ring the leading metric coefficients are determined, via (22), by the components of the three-form flux. Thus the geometry can sometimes respond to smooth out what could have been singularities at the sources.…”

“…Having found the G i , one can use equations (22) to find the metric functions Z i . Given a distribution of branes, the term on the right hand side of equation (22) contains both the explicit G∧G term, as well as an implicit "fundamental" brane density, ρ i ( x).…”

R2corrections for 5D black holes and rings

“…They are also of special interest as descendants of the interesting 11D R 4 terms [8,9]. These terms correct the entropy of both the 5D black ring [10] and the 5D BMPV spinning black hole [11]. We find that the macroscopic black…”

More rings to rule them all: fragmentation, 4D↔ 5Dand split-spectral flows

“…(3.6) by taking the limit R T N → ∞. The conventions of [14], [15] differ from [20] by rescaling of charges; in this note we continue using the latter.…”

“…3 A black ring in R 4 ( see [14], [15], [17], [18] ) can be extracted as a special case of eq. (3.6) by taking the limit R T N → ∞.…”