2020
DOI: 10.1112/jlms.12380
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The fundamental group of the p‐subgroup complex

Abstract: We study the fundamental group of the p‐subgroup complex of a finite group G. We show first that π1false(A3(A10)false) is not a free group (here A10 is the alternating group on ten letters). This is the first concrete example in the literature of a p‐subgroup complex with non‐free fundamental group. We prove that, modulo a well‐known conjecture of Aschbacher, π1false(Ap(G)false)=π1false(Ap(SG)false)∗F, where F is a free group and π1false(Ap(SG)false) is free if SG is not almost simple. Here SG=normalΩ1false(Gf… Show more

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Cited by 2 publications
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“…We give some applications of Theorem 4.1. The following results depend on the results obtained on the fundamental group of the -subgroup posets [12] and the almost-simple case of the conjecture [4]. Proof.…”
Section: Proof Ifmentioning
confidence: 94%
See 1 more Smart Citation
“…We give some applications of Theorem 4.1. The following results depend on the results obtained on the fundamental group of the -subgroup posets [12] and the almost-simple case of the conjecture [4]. Proof.…”
Section: Proof Ifmentioning
confidence: 94%
“…In this way, we can work with smaller subposets and apply inductive arguments. This approach has its roots in our previous work with Minian on the fundamental group of these complexes [12]. The poset N( ) was also considered by Segev and Webb [18,19].…”
Section: Introductionmentioning
confidence: 98%