“…. , λ r ) n, r ≥ 2 and λ = (n − 1, 1) or (2, 1 n−2 ), then the sign of 1 ξ λ is equal to (−1) n−λ 1 −1 (see also [2,3,[10][11][12][13] for other related results). It was conjectured in [6,7] that the alternating sign property holds for the matching derangement graph.…”