“…To estimate the heat in Equation (53), we implicitly assumed µ(A, Z − 2, P β , B ) < µ(A, Z, P β , B ), which generally holds for even A nuclei, but not necessarily for odd A nuclei. In the latter case, we typically have (43), this implies that γ β e (A, Z) < γ β e (A, Z − 1). In other words, as the pressure reaches P β (A, Z, B ), the nucleus (A, Z) decays, but the daughter nucleus (A, Z − 1) is actually stable against electron capture, and therefore, no heat is released Q(A, Z, B ) = 0.…”