“…In our example, we compute that ϕ(2) = 14, ϕ(14) = 12, ϕ(12) = 17, ϕ(17) = 19, and ϕ(19) = 2, so one of the boundary cycles is the orbit(2,14,12,17,19). The other three boundary cycles in this example are(4,20,21,22,18,10,15),(6,16,8), and (1,3,5,7,9,11,13); see Figure2 (right).We note that each boundary cycle corresponds to a connected component of the complement of the graph. Therefore, the boundary cycles will allow us to identify the Reeb graph of the uncovered region in spacetime.…”