4-Chloro-<i>N</i>-(3,4-dimethylphenyl)benzamide

The title compound, C16H17NO, crystallizes with two molecules in the asymmetric unit. The conformation of the N—H bond is anti to the meta-methyl substituent in the aniline ring in the first molecule and syn in the second molecule. The dihedral angles between the two benzene rings are 52.6 (1) and 10.5 (1)° in the first and second molecules, respectively. Intermolecular N—H⋯O hydrogen bonds link the molecules into chains running along the b axis of the crystal.

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N-(3,4-Dimethylphenyl)-4-methylbenzamide

Gowda

Tokarčík

Kožı́šek

et al. 2009

Acta Cryst E

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4-Chloro-N-(3,4-dimethylphenyl)benzamide

Abstract: In the title compound, C15H14ClNO, the N—H bond is trans to the C=O bond. The dihedral angle between the two aromatic rings is 5.5 (2)°. In the crystal, intermolecular N—H⋯O hydrogen bonds link the molecules into chains running along the a axis.

Cited by 1 publication

References 7 publications

N-(3,4-Dimethylphenyl)-4-methylbenzamide

N-(3,4-Dimethylphenyl)-4-methylbenzamide

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4-Chloro-N-(3,4-dimethylphenyl)benzamide

Abstract: In the title compound, C15H14ClNO, the N—H bond is trans to the C=O bond. The dihedral angle between the two aromatic rings is 5.5 (2)°. In the crystal, inter­molecular N—H⋯O hydrogen bonds link the mol­ecules into chains running along the a axis.

Cited by 1 publication

References 7 publications

N-(3,4-Dimethylphenyl)-4-methylbenzamide

N-(3,4-Dimethylphenyl)-4-methylbenzamide

Contact Info

Product

Resources

About

Abstract: In the title compound, C15H14ClNO, the N—H bond is trans to the C=O bond. The dihedral angle between the two aromatic rings is 5.5 (2)°. In the crystal, intermolecular N—H⋯O hydrogen bonds link the molecules into chains running along the a axis.