The decolorization of bromine is a well known, classical test in organic chemistry for an unsaturated bond [2]. Reactions of this type take place readily and without the use of any kind of catalyst. Ethyl 1-allyl-4-hydroxy-2-oxo-1,2-dihydroquinoline-3-carboxylate (1) behaves in just this way under these conditions and it was initially suggested that its bromination is simply the usual addition of halogen at the allyl fragment double bond to form the 2,3-dibromopropyl derivative [3]. The basic argument supporting this conclusion was the fact that, after treatment of the compound obtained with excess sodium methylate in methanol and subsequent acidification of the reaction mixture with aqueous hydrochloric acid, the product methyl 1-acetonyl-4-hydroxy-2-oxo-1,2-dihydroquinoline-3-carboxylate (2) was formed (whose structure was confirmed by X-ray data [1]). The fully expected transesterification and, mainly, the well established ability of vicinal dibromides to be dehydrobrominated to acetylenes with a terminal triple bond in the presence of strong bases (which, in turn, are hydrated via a Kucherov reaction to the corresponding ketones [4]) could quite logically explain the experimental results.However, further investigation has cast doubt that the N-allyl substituted ester 1 is actually brominated to 1-(2,3-dibromopropyl)-3-ethoxycarbonyl-4-hydroxy-2-oxo-1,2-dihydroquinoline.In the first place, the bromination product appears to be extremely stable to hydrolysis in a mixture of hydrochloric and acetic acids with a low water content and this is atypical for this class of compound. As is known [5] ethyl 1-R-4-hydroxy-2-oxo-1,2-dihydroquinoline-3-carboxylate is hydrolyzed under these conditions without complication and the example of preparing acid 3 confirms again confirms this. In the second place the reaction with less powerful bases than sodium methylate leads to a totally different compound which is, in fact,