2012
DOI: 10.4086/toc.2012.v008a023
|View full text |Cite
|
Sign up to set email alerts
|

Untitled

Abstract: We show that unless NP ⊆ RTIME(2 poly(log n) ), there is no polynomial-time algorithm approximating the Shortest Vector Problem (SVP) on n-dimensional lattices in the p norm (1 ≤ p < ∞) to within a factor of 2 (log n) 1−ε for any ε > 0. This improves the previous best factor of 2 (log n) 1/2−ε under the same complexity assumption due to Khot (J. ACM, 2005). Under the stronger assumption NP RSUBEXP, we obtain a hardness factor of n c/ log log n for some c > 0.Our proof starts with Khot's SVP instances that are … Show more

Help me understand this report
View preprint versions

Search citation statements

Order By: Relevance

Paper Sections

Select...
5

Citation Types

0
22
0

Year Published

2012
2012
2021
2021

Publication Types

Select...
4
3

Relationship

0
7

Authors

Journals

citations
Cited by 30 publications
(22 citation statements)
references
References 24 publications
0
22
0
Order By: Relevance
“…• the hardness of SVP for subpolynomial factors n 1/O(log log n) under the assumption that NP is not in subexponential time, as in [14,12], thus matching the strongest known hardness results for SVP, but under probabilistic reductions with onesided error. We regard our results as a partial derandomization of the reductions [14,12] with two-sided error, and a step toward an NP-hardness proof for SVP under deterministic reductions.…”
Section: Introductionmentioning
confidence: 94%
See 3 more Smart Citations
“…• the hardness of SVP for subpolynomial factors n 1/O(log log n) under the assumption that NP is not in subexponential time, as in [14,12], thus matching the strongest known hardness results for SVP, but under probabilistic reductions with onesided error. We regard our results as a partial derandomization of the reductions [14,12] with two-sided error, and a step toward an NP-hardness proof for SVP under deterministic reductions.…”
Section: Introductionmentioning
confidence: 94%
“…Our results We present a new, simpler proof that SVP is NP-hard to approximate within any constant factor which goes back to the geometrically appealing approach of [20] and avoids the introduction of additional probabilistic techniques from [14,12]. In particular, we prove…”
Section: Introductionmentioning
confidence: 99%
See 2 more Smart Citations
“…On the negative side, SVP in 2 is NP-hard (under randomized reductions) to solve exactly, or even to approximate to within any constant factor [1,9,34,29]. Many more hardness results are known for other p norms and under stronger complexity assumptions than P = NP [17,14,43,22,35]. CVP is NP-hard to approximate to within n c/ log log n factors for some constant c > 0 [4,15], where n is the dimension of the lattice.…”
Section: Introductionmentioning
confidence: 99%