“…Then |P 7 | | 7 3 . Since n 7 = s (9,2,3,2), (7,3,3,2), (8,3,3,2), (6,4,3,2), (7,4,3,2), (4,5,3,2), (5,5,3,2), (3,6,3,2), (1,7,3,2), (2,7,3,2), (9, 7, 1, 1), (9, 5, 2, 1), (8, 6, 2, 1), (9, 6, 2, 1), (6, 7, 2, 1), (7, 7, 2, 1), (4, 7, 3, 1), (5,7,3,1), (5,6,6,3,1), (6,…”