2009
DOI: 10.1090/s0002-9939-09-09814-1
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A combinatorial interpretation of the Legendre-Stirling numbers

Abstract: Abstract. The Legendre-Stirling numbers were discovered in 2002 as a result of a problem involving the spectral theory of powers of the classical secondorder Legendre differential expression. Specifically, these numbers are the coefficients of integral composite powers of the Legendre expression in Lagrangian symmetric form. Quite remarkably, they share many similar properties with the classical Stirling numbers of the second kind which, as shown by Littlejohn and Wellman, are the coefficients of integral powe… Show more

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Cited by 43 publications
(46 citation statements)
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“…For an excellent account of Stirling numbers of the first and second kind, see Comtet's text [5,Chapter V]. This paper is a continuation of the recent work of Andrews and Littlejohn in [3], where the authors obtained a combinatorial interpretation of the Legendre-Stirling numbers. The contents of this paper are as follows.…”
Section: Introductionmentioning
confidence: 82%
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“…For an excellent account of Stirling numbers of the first and second kind, see Comtet's text [5,Chapter V]. This paper is a continuation of the recent work of Andrews and Littlejohn in [3], where the authors obtained a combinatorial interpretation of the Legendre-Stirling numbers. The contents of this paper are as follows.…”
Section: Introductionmentioning
confidence: 82%
“…It is natural to ask: what do the Legendre-Stirling numbers count? Andrews and Littlejohn gave a combinatorial interpretation of these numbers in [3].…”
Section: A Combinatorial Interpretation Of the Legendre-stirling Numbersmentioning
confidence: 99%
See 1 more Smart Citation
“…and satisfy the recurrence relation LS (n, k) = LS (n − 1, k − 1) + k(k + 1)LS (n − 1, k), with the initial conditions LS (0, 0) = 1 and LS (0, k) = 0 for k ≥ 1. Andrews and Littlejohn [3] discovered that LS (n, k) is the number of Legendre-Stirling set partitions of the set {1 1 , 1 2 , 2 1 , 2 2 , . .…”
mentioning
confidence: 99%
“…In particular, let <> denote the empty zero box. For example, {1, 1, 3}{2, 2} < 3 >∈ LS (3,2). A classical result of Andrews and Littlejohn [3, Theorem 2] says that LS (n, k) = #LS(n, k).…”
Section: Legendre-stirling Set Partitionsmentioning
confidence: 99%