“…, t − 1}, for a total of nt distances. Instead, Chang's [3]d is d i, i + s 2 t 2 + s 1 t + s 0 mod n ≡ d i, i + s 2 t 2 mod n + d i + s 2 t 2 mod n, i + s 2 t 2 + s 1 t mod n + d i + s 2 t 2 + s 1 t mod n, i + s 2 t 2 + s 1 t + s 0 mod n for all i ∈ {0, 1, . .…”