“…If there is a dirty triple {a, b, c} forming three dirty pairs contained in D, namely, {a, b}, {b, c}, {a, c} ∈ D, then remove these three pairs from D. Branch into all six possible orders of a, b, and c. In each subcase, if the corresponding order is not consistent with L, discard this subcase, otherwise, add the corresponding order to L and decrease the parameter according to this subcase. The worst-case branching vector of this case is (3,4,4,5,5,6), giving a branching number 1.52. To see this, note that we only consider instances with at least three votes, since Kemeny Score is polynomial-time solvable for only two votes.…”