1987
DOI: 10.1215/ijm/1256063576
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A generalization of Halász's theorem to Beurling's generalized integers and its application

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Cited by 15 publications
(10 citation statements)
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“…I proposed some years back the following conjecture: Such a conjecture is trivially true under the Riemann Hypothesis. In this respect, we note that [23] proves that in case of the Beurling's generalized integers, one can have M P (x) = o(x) without having ψ(x) ∼ x. This reference has been kindly shown to me by Harold Diamond whom I warmly thank here.…”
Section: Introductionmentioning
confidence: 74%
“…I proposed some years back the following conjecture: Such a conjecture is trivially true under the Riemann Hypothesis. In this respect, we note that [23] proves that in case of the Beurling's generalized integers, one can have M P (x) = o(x) without having ψ(x) ∼ x. This reference has been kindly shown to me by Harold Diamond whom I warmly thank here.…”
Section: Introductionmentioning
confidence: 74%
“…[6], [9,Chap. 14], [16]. Here we study the Beurling version of the assertion M(x) = o(x) and show this can be deduced (a) from the PNT under an Oboundedness condition N(x) = O(x) or (b) from a Chebyshev-type upper bound assuming N(x) ∼ ax (for a > 0) and the integral condition (3.2) (below).…”
Section: Introductionmentioning
confidence: 94%
“…Our method is inspired by W.-B. Zhang's proof of a Halász-type theorem for Beurling primes [16]. Our first step is to replace M(x) = o(x) by an equivalent asymptotic relation.…”
Section: Chebyshev Hypothesismentioning
confidence: 99%
“…A function f : N −→ C is said to be multiplicative on N if f (1) = 1 and f (mn) = f (m)f (n) whenever (m, n) = 1. Such an f is said to be completely multiplicative [5,16] if we also have f (mn) = f (m)f (n) for all values of m, n ∈ N , where (m, n) is defined as the largest ginteger that divides both m and n. We define the generalised Liouville function on N , is an example of completely multiplicative function, to be λ P (1) = 1 and λ P (n) = (−1)…”
Section: Completely Multiplicative Function On Nmentioning
confidence: 99%