“…Note that gcdpx n ´ax i ´b, x n ´cx i ´dq " gcdpx n ´ax i ´b, x n ´ax i ´b ṕx n ´cx i ´dqq " gcdpx n ´ax i ´b, pc ´aqx i `pd ´bqq. Using a similar argument, we have the following, gcdpx n ´ax i ´b, x n ´cx i ´dq " gcdpx n ´ax i ´b, pc ´aqx i `pd ´bqq " gcdpx n ´ax i ´b, x i `pd ´bqpc ´aq ´1q " gcdpx n ´ax i ´b `a ¨px i `pd ´bqpc ´aq ´1q, x i `pd ´bqpc ´aq ´1q " gcdpx n `apd ´bqpc ´aq ´1 ´b, x i `pd ´bqpc ´aq ´1q Therefore, by Theorem 4.1 in [4] gcdpx n ´ax i ´b, x n ´cx i ´dq is either 1 or a binomial of degree gcdpn, iq. Lemma 8.4.…”