2017 IEEE 56th Annual Conference on Decision and Control (CDC) 2017
DOI: 10.1109/cdc.2017.8263792
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A hybrid observer for a distributed linear system with a changing neighbor graph

Abstract: A hybrid observer is described for estimating the state of an m > 0 channel, n-dimensional, continuous-time, distributed linear system of the forṁ x = Ax, yi = Cix, i ∈ {1, 2, . . . , m}. The system's state x is simultaneously estimated by m agents assuming each agent i senses yi and receives appropriately defined data from each of its current neighbors. Neighbor relations are characterized by a time-varying directed graph N(t) whose vertices correspond to agents and whose arcs depict neighbor relations. Agent… Show more

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Cited by 33 publications
(31 citation statements)
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“…(i) For a given sub-state j, there may not exist a common spanning tree rooted at node j in each graph G[k], k ∈ N. (ii) Assuming that a specific spanning tree rooted at node j is guaranteed to repeat at various points in time (not necessarily periodically), is restrictive, and qualifies as only a special case of conditions (C1)-(C3). (iii) Suppose for simplicity that G[k] is strongly-connected at each time-step (as in [11]), and hence, there exists a spanning tree T j [k] rooted at node j in each such graph. For estimating sub-state j, suppose consensus at time-step k is performed along the spanning tree T j [k].…”
Section: Problem Formulation and Backgroundmentioning
confidence: 99%
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“…(i) For a given sub-state j, there may not exist a common spanning tree rooted at node j in each graph G[k], k ∈ N. (ii) Assuming that a specific spanning tree rooted at node j is guaranteed to repeat at various points in time (not necessarily periodically), is restrictive, and qualifies as only a special case of conditions (C1)-(C3). (iii) Suppose for simplicity that G[k] is strongly-connected at each time-step (as in [11]), and hence, there exists a spanning tree T j [k] rooted at node j in each such graph. For estimating sub-state j, suppose consensus at time-step k is performed along the spanning tree T j [k].…”
Section: Problem Formulation and Backgroundmentioning
confidence: 99%
“…Node 1 is the only node with non-zero measurements, and thus acts as the source node for this network. Suppose for simplicity that it perfectly measures the state at all timesteps, i.e., its state estimate isx 1 [k] = x[k], ∀k ∈ N. Given this setup, a standard consensus based state estimate update rule would take the form (see for example [5], [6], [11]): (7) where the weights w ij [k] are non-negative, and satisfy…”
Section: An Illustrative Examplementioning
confidence: 99%
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