2020
DOI: 10.1090/ecgd/350
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A locally hyperbolic 3-manifold that is not homotopy equivalent to any hyperbolic 3-manifold

Abstract: We construct a locally hyperbolic 3-manifold M M such that π 1 ( M ) \pi _1(M) has no divisible subgroups. We then show that M M is not homotopy equivalent to any complete hyperbolic manifold.

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Cited by 6 publications
(7 citation statements)
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“…Indeed, consider all manifolds M ∈ M B such that for all i ∈ N every component U i := M i \ M i−1 is acylindrical. By the main results of [6] this guarantees that M is in fact hyperbolic, which is in general not the case, see [5,7]. We can thus think of a (hyperbolic) metric g on M as a gluing of (hyperbolic) metrics g i on the U i 's and so it makes sense to investigate the glueing of pairs U i , U i+1 via skinning maps.…”
Section: Effective Computationsmentioning
confidence: 99%
“…Indeed, consider all manifolds M ∈ M B such that for all i ∈ N every component U i := M i \ M i−1 is acylindrical. By the main results of [6] this guarantees that M is in fact hyperbolic, which is in general not the case, see [5,7]. We can thus think of a (hyperbolic) metric g on M as a gluing of (hyperbolic) metrics g i on the U i 's and so it makes sense to investigate the glueing of pairs U i , U i+1 via skinning maps.…”
Section: Effective Computationsmentioning
confidence: 99%
“…Remark 2.4. By [Cre18a] one can also show that the manifold N is not homotopy equivalent to any hyperbolic 3-manifold.…”
Section: Locally Hyperbolic Not Hyperbolic 3-manifoldsmentioning
confidence: 99%
“…However, the 3-manifold M ∞ is homotopy equivalent to a complete hyperbolic 3-manifold. In [Cre18a] we improved the above example by building a 3-manifold N ∈ M B such that N is not homotopy equivalent to any complete hyperbolic 3-manifold.…”
Section: Introductionmentioning
confidence: 99%
“…By work of Souto–Stover [31] and Cremaschi–Souto [13] and Cremaschi [10, 12] it is not hard to build hyperbolizable infinite type 3‐manifolds that are homeomorphic to Cantor set complements in the 3‐sphere double-struckS3$\mathbb {S}^3$. In particular, in [13], the manifold of Example 2 can be extended to be a Cantor set complement showing, for example, how one can have a hyperbolizable Cantor set complement in double-struckS3$\mathbb {S}^3$ whose fundamental group is not residually finite.…”
Section: Introductionmentioning
confidence: 99%