2017
DOI: 10.1093/qmath/hax001
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A lower bound for the least prime in an Arithmetic progression

Abstract: Abstract. Fix k a positive integer, and let be coprime to k. Let p(k, ) denote the smallest prime equivalent to (mod k), and set P (k) to be the maximum of all the p(k, ). We seek lower bounds for P (k). In particular, we show that for almost every k one has P (k) φ(k) log k log 2 k log 4 k/ log 3 k, answering a question of Ford, Green, Konyangin, Maynard, and Tao. We rely on their recent work on large gaps between primes. Our main new idea is to use sieve weights to capture not only primes, but also small mul… Show more

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Cited by 14 publications
(11 citation statements)
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“…For large x, computations of [12, section 3.4] suggest that τ is strictly greater than one; with this in mind, we expect at most finitely many exceptions to inequality (14) for any fixed q. In section 3 we will compare this heuristic prediction with results of computations.…”
Section: 2mentioning
confidence: 94%
See 1 more Smart Citation
“…For large x, computations of [12, section 3.4] suggest that τ is strictly greater than one; with this in mind, we expect at most finitely many exceptions to inequality (14) for any fixed q. In section 3 we will compare this heuristic prediction with results of computations.…”
Section: 2mentioning
confidence: 94%
“…The above is valid for large n and x. To make estimate (12) applicable to moderate n, we add a semi-empirical correction term of size O q (n) (motivated in part by heuristics of [14]):…”
Section: The Nth Record Gap R(n Q R)mentioning
confidence: 99%
“…Both heuristic probabilistic arguments and numerical evidence indicate that P(k) satisfies the much sharper bound P(k) = O(𝜑(k) log 2 k) = O(k log 2 k), where 𝜑 stands for Euler's totient function. More precisely, based on such evidence [38], Li, Pratt and Shakan conjecture that…”
Section: The Smallest Prime Number In An Arithmetic Progressionmentioning
confidence: 99%
“…GRH implies that L ď 2 `ε for every ε ą 0 and it is known that L ď 5, see [33]. Furthermore, one cannot have L ă 1, see [26] for accurate lower bounds. Theorem 1.5 shows that the analogue of the Linnik constant for polynomials of given degree is at most 1 `ε for every ε ą 0.…”
Section: Introductionmentioning
confidence: 99%