2011
DOI: 10.1007/s00023-011-0143-y
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A New Recursion Relation for the 6j-Symbol

Abstract: The 6j-symbol is a fundamental object from the re-coupling theory of SU(2) representations. In the limit of large angular momenta, its asymptotics is known to be described by the geometry of a tetrahedron with quantized lengths. This article presents a new recursion formula for the square of the 6j-symbol. In the asymptotic regime, the new recursion is shown to characterize the closure of the relevant tetrahedron. Since the 6j-symbol is the basic building block of the Ponzano-Regge model for pure three-dimensi… Show more

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Cited by 11 publications
(26 citation statements)
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“…j P p (j i , j)P q (j i , j) . (B14) 14 In details, 12 {j i }, j β |{j i }, W 4 = (−1) J −2j β 4 i=1 (2j i )! (j β + j 3 − j 4 )!…”
Section: B the 4-valent Casementioning
confidence: 99%
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“…j P p (j i , j)P q (j i , j) . (B14) 14 In details, 12 {j i }, j β |{j i }, W 4 = (−1) J −2j β 4 i=1 (2j i )! (j β + j 3 − j 4 )!…”
Section: B the 4-valent Casementioning
confidence: 99%
“…While some basic properties have been known for several decades, a need for new results involving more and more spins have appeared and have led to some interesting progress. They come from various areas of physics, like quantum information [4,5], semi-classical approximations for quantum angular momenta [6,7], and quantum gravity [8][9][10][11][12][13][14][15].…”
mentioning
confidence: 99%
“…From this approach the full expansion can be computed in principle, however in a very lengthy way. We derive a recursion relations of the Ward-Takesaki type, which is surprisingly similar to the one invented in [36,37] however in very different context, that, basically can be used in the asymptotic expansion to derive the NLO in a more concise way. Moreover, we can show explicitly that the consecutive terms in the expansion (1.1) are of the conjectured 'sin/cos' form.…”
Section: Problem Of the Next To Leading Order (Nlo) And Complete Asymmentioning
confidence: 97%
“…We will now derive a recursion relation for the full 6j symbol using a similar idea as in [36,37] that, we hope, can serve to compute the NLO expansion in more concise way.…”
Section: Leading Order Expansion and A Recursion Relation For The 6j mentioning
confidence: 99%
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