“…, 7 ∈ R. The solutions (2, 3, 1, 10), (4, 5, 1, 11), (13,4,1,13), (24,2,2,24), and (82, 1, 7, 82) show that 10, 11, 13, 24, 82 ∈ B. Then we have 8, 93, 94 ∈ R by considering (24,24,8,82), (11,11,10,93), and (13,13,10,94). Therefore, (3,93,8,94) is a red solution, a contradiction.…”