2005
DOI: 10.1155/jia.2005.459
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A note on Ostrowski's inequality

Abstract: This paper deals with the problem of estimating the deviation of the values of a function from its mean value. We consider the following special cases: (i) the case of random variables (attached to arbitrary probability fields); (ii) the comparison is performed additively or multiplicatively; (iii) the mean value is attached to a multiplicative averaging process.

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Cited by 8 publications
(3 citation statements)
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“…Until nowadays, the works of Chebyshev, Ostrowski, and Grüss have continued to inspire active mathematical research focused on inequalities/estimates of (co)variance. This fact is clearly documented by rich literature dealing with the subject [20][21][22][23][24][25][26][27][28][29][30][31][32][33][34][35][36][37]. For the purposes of the present article we specifically highlight an inequality for covariance which was derived recently by He and Wang in [20].…”
Section: Introductionmentioning
confidence: 84%
“…Until nowadays, the works of Chebyshev, Ostrowski, and Grüss have continued to inspire active mathematical research focused on inequalities/estimates of (co)variance. This fact is clearly documented by rich literature dealing with the subject [20][21][22][23][24][25][26][27][28][29][30][31][32][33][34][35][36][37]. For the purposes of the present article we specifically highlight an inequality for covariance which was derived recently by He and Wang in [20].…”
Section: Introductionmentioning
confidence: 84%
“…Florea and Niculescu in Reference [20] treated the problem of estimating the deviation of the values of a function from its mean value. The estimation of the deviation of a function from its mean value is characterized below.…”
Section: From the Relationmentioning
confidence: 99%
“…Next, we can write some equalities and inequalities, using several results from Section 2, related to variance, covariance and the standard deviation of vectors x, y ∈ X. Therefore, from relations (8), (10), (11), (15), (18)- (20), (22), (25), we obtain the following relations: where a, b ∈ R. By dividing by u = 0, we deduce the relation a x u + be = w u , where e = u u , so e = 1. Therefore, we obtain a = ( w u , x u |e)…”
Section: From the Relationmentioning
confidence: 99%