“…In case one of the first two conditions holds, the mapping from S onto the rectangular band T = A/ρ 1 × A/ρ 2 that maps each triple (x, w, y) ∈ S to (x/ρ 1 , y/ρ 2 ) is a continuous homomorphism onto a semigroup from CS that distinguishes u and v. Moreover, its kernel congruence is contained in ρ, which implies that T ∈ Σ , contradicting the assumption that Σ satisfies u = v. Hence, we may assume that (a, c) ∈ ρ 1 and (b, d) ∈ ρ 2 , so that g ω−1 h does not belong to N ρ . As in the proof of Theorem 8.1, we deduce that there is a clopen normal subgroup K of Ω X G such that N ρ ⊆ K and g ω−1 h / ∈ K. Since K contains N ρ , the triple (ρ 1 , ρ 2 , K) still satisfies the analogues of conditions (12) and (13). Hence, by Theorem 9.1, it defines a congruenceρ on S. Since K has finite index in Ω X G, the congruenceρ has finite index in S. The reader may easily verify that, since ρ is a closed congruence on S and K is a closed subgroup of Ω X G, the congruenceρ is still closed, whence the natural mapping S → S/ρ is a continuous homomorphism.…”