“…Then deg(P ) = N (P ) = 3, H(P 2 ) = H(1+2x+x 2 +2x 3 +2x 4 +x 6 ) = 2, giving Q 2 (P ) = 8/9. Combined with Theorem 1 this implies the main result of [2]. Note that the polynomial 1 + x 2 + x 3 (which is reciprocal to 1 + x + x 3 ) already features as extremal in the following well-known problem: find f (n) = sup N (P )=n, P Newman inf |z|=1 |P (z)|.…”