2014 International Conference on Advances in Computing, Communications and Informatics (ICACCI) 2014
DOI: 10.1109/icacci.2014.6968324
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A Radix-2 DIT FFT with reduced arithmetic complexity

Abstract: The efficient computation of Discrete Fourier Transform (DFT) is an important issue as it is used in almost all fields of engineering for signal processing. This paper presents a different form of Radix-2 Fast Fourier Transform (FFT) based on Decimation in time (DIT) to compute DFT, discuss their implementation issues and derive it's signal to quantization noise ratio(SQNR) that further decreases the number of multiplication counts without affecting the number of additions of Radix-2 discrete Fourier Transform… Show more

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Cited by 11 publications
(3 citation statements)
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“…A modified version of the split-radix proposed in [125] lowers the flop count by ~5.6% without sacrificing numerical accuracy. In [126], by scaling the Twiddle Factor 4 , the authors decrease the number of multiplication counts without affecting the number of additions. In addition, this modification also improves the signal-to-quantization noise ratio (SQNR) by more than 1.6 dB.…”
Section: Fft/ifft Functionsmentioning
confidence: 99%
“…A modified version of the split-radix proposed in [125] lowers the flop count by ~5.6% without sacrificing numerical accuracy. In [126], by scaling the Twiddle Factor 4 , the authors decrease the number of multiplication counts without affecting the number of additions. In addition, this modification also improves the signal-to-quantization noise ratio (SQNR) by more than 1.6 dB.…”
Section: Fft/ifft Functionsmentioning
confidence: 99%
“…Now the x(n) sequences for the first and second part of X(k)even will be X(k)even,1st part = x(0), x(4), x (8), x (12); X(k)even,2nd part = x(2), x(6), x (10), x (14); The equation for X(k)odd will be…”
Section: =0mentioning
confidence: 99%
“…W4 kn ….…..….. (3) where n = 0, 1, 2, 3, and N = 16. Now the x(n) sequences for the first and second part of X(k)odd will be X(k)odd,1st part = x(1), x(5), x (9), x(13); X(k)odd,2nd part = x(3), x (7), x (11), x (15); Now putting the value of x(n) sequences in the equation 2, we get the even sequences X(0)even = x(0).W4 0 + x(4).W4 0 + x (8).W4 0 + x (12).W4 0 + W8 0 [x(2).W4 0 + x(6).W4 0 + x (10).W4 0 + x (14) (2).W4 0 + x (6).W4 3 + x (10).W4 6…”
Section: =0mentioning
confidence: 99%