2018
DOI: 10.19086/da.3659
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A short proof of the middle levels theorem

Abstract: Consider the graph that has as vertices all bitstrings of length 2n + 1 with exactly n or n + 1 entries equal to 1, and an edge between any two bitstrings that differ in exactly one bit. The well-known middle levels conjecture asserts that this graph has a Hamilton cycle for any n ≥ 1. In this paper we present a new proof of this conjecture, which is much shorter and more accessible than the original proof.

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Cited by 25 publications
(63 citation statements)
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“…This paper complements previous work [5] on reinterpreting the middle-levels theorem [6,8] via a numeral system that enumerates all ordered trees. Let 0 < k ∈ Z and let n = 2k + 1.…”
Section: Introductionsupporting
confidence: 60%
“…This paper complements previous work [5] on reinterpreting the middle-levels theorem [6,8] via a numeral system that enumerates all ordered trees. Let 0 < k ∈ Z and let n = 2k + 1.…”
Section: Introductionsupporting
confidence: 60%
“…By this definition, every pair of almostorthogonal chain decompositions is edge-disjoint, but not necessarily vice versa. The main application of edge-disjoint chain decompositions in [GJM + 18] was to construct cycle factors in subgraphs of Q n induced by an interval of levels around the middle, with the goal of generalizing the recent proof of the middle levels conjecture by Mütze [Müt16] (see also [GMN18]). It is also easy to check that Q n admits at most b n pairwise edge-disjoint chain decompositions.…”
Section: Our Resultsmentioning
confidence: 99%
“…It was hoped that people can find two 1-factors which form a Hamiltonian cycle [17]. Yet after extensive studies for thirty years the conjecture itself was settled by Mütze [21]; see also [14] for a recent and shorter proof and see [22] for an optimal algorithm for computing such a Hamiltonian cycle. Moreover, Mütze and Su [23] settles the Hamiltonian problem for all the bipartite Kneser graphs.…”
Section: Motivation and Related Workmentioning
confidence: 99%