2004
DOI: 10.1016/j.jcta.2004.03.009
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A variant of Kemnitz Conjecture

Abstract: For any integer nX3; by gðZ n "Z n Þ we denote the smallest positive integer t such that every subset of cardinality t of the group Z n "Z n contains a subset of cardinality n whose sum is zero. Kemnitz (Extremalprobleme fu¨r Gitterpunkte, Ph.D. Thesis, Technische Universita¨t Braunschweig, 1982) proved that gðZ p "Z p Þ ¼ 2p À 1 for p ¼ 3; 5; 7: In this paper, as our main result, we prove that gðZ p "Z p Þ ¼ 2p À 1 for all primes pX67: r 2004 Elsevier Inc. All rights reserved. MSC: primary 11B75; secondary 20… Show more

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Cited by 20 publications
(17 citation statements)
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“…Then the equality holds for n = 2 (trivial) and n = 3 [34,Hilfssatz 3]. If p is a prime with p ≥ 67, then g(C p ⊕ C p ) = s(C p ) = 2p − 1; see Theorem 1.1 and [29].…”
Section: Definition 21 We Denote Bymentioning
confidence: 99%
“…Then the equality holds for n = 2 (trivial) and n = 3 [34,Hilfssatz 3]. If p is a prime with p ≥ 67, then g(C p ⊕ C p ) = s(C p ) = 2p − 1; see Theorem 1.1 and [29].…”
Section: Definition 21 We Denote Bymentioning
confidence: 99%
“…When G is cyclic of order m, we have h(G, k) ≥ k + 1 provided m − ⌊m/4⌋ − 2 ≤ k ≤ m − 2 (see [8]); h(G, k) ≥ k + 1 provided m is prime with 1 ≤ k ≤ m − 2 (see [11]); h(G, m − 2) = m − 1 (see [1] or [15]); and h(G, m − 3) = m − 1 (see [7]). …”
Section: Results We Have the Following Open Problemmentioning
confidence: 99%
“…In particular, g(C 2 3 ) = 5. More recently Gao and Thangadurai [4] showed g(C 2 p ) = 2p−1 for prime p ≥ 67 and g(C 2 4 ) = 9. In [2] we can find other values for elementary 3-group; for example g(C 3 3 ) = 10, g(C 3 3 ) = 21, g(C 5 3 ) = 46 and 112 ≤ g(C 6 3 ) ≤ 114 [1,7,8,12].…”
Section: Remark 2 Kemnitz Showed G(cmentioning
confidence: 99%