“…For each possibility we compute y = 2592 mod 3240 (using Lemma 8.13), and so y = 2592. The cases (f 2 , f 3 ) = (20,13), (24,18) give X 4 (p 0 ) < 0. Thus the only surviving cases are (f 1 , f 2 , f 3 ) = (4, 12, 3), (4,16,8) with x = 0 and y = 2592.…”