Mono‐organotin(IV) and tin(IV) derivatives of 2‐mercaptopyridine (HSPy) and 2‐mercaptopyrimidine (HSPym), RSnL3 (R=Me, n‐Bu, Ph; L=SPy, SPym; R=Bz=benzyl, o‐ClBz, o‐ClC6H4, p‐ClC6H4, o‐tolyl, p‐tolyl; L=SPy), RSnClL2 (R=Me, n‐Bu, Ph; L=SPy, SPym), RSnCl2L (R=Me, n‐Bu; L=SPy, SPym) and SnCl4−nLn (L=SPy, SPym; n=2, 4) were obtained from RSnCl3 or SnCl4 and NaL or by neutralization (R=Ph, p‐tolyl; L=SPy, SPym). RSnClL2 and RSnCl2L were better prepared by comproportionation of RSnCl3 and RSnL3.
MeSn(SPy)3 and PhSn(SPy)3·1.5CHCl3 crystals, as determined by single‐crystal X‐ray diffraction, are monoclinic. In the discrete monomeric RSn(SPy)3 units, three bidentate SPy ligands together with R form a distorted pentagonal bipyramid around tin. One S and the C(R) atom are in the axial positions. Two S atoms and three N atoms form the pentagonal plane.
From 119Sn Mössbauer and IR data, analogous structures are inferred for the other solid RSnL3 compounds, except for R=Bz, o‐ClBz, o‐ClC6H4 and o‐tolyl, in which tin would be hexacoordinated. In the compounds RSnClL2 and RSnCl2L, tin is at the center of an octahedron or a trigonal bipyramid, respectively. For Sn(SPym)4 and SnCl2(SPym)2, the same type of octahedral structure as was previously found for Sn(SPy)4·HSPy and SnCl2(SPy)2 is proposed.
According to IR and 1H, 13C and 119Sn NMR data, the solid‐state molecular structures are retained in chloroform and dimethyl sulfoxide solution. © 1997 John Wiley & Sons, Ltd.