2007
DOI: 10.1007/s10773-007-9369-3
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Affine Hamiltonians in Higher Order Geometry

Abstract: Affine Hamiltonians are defined in the paper and their study is based especially on the fact that in the hyperregular case they are dual objects of Lagrangians defined on affine bundles, by mean of natural Legendre maps. The variational problems for affine Hamiltonians and Lagrangians of order k ≥ 2 are studied, relating them to a Hamilton equation. An Ostrogradski type theorem is proved: the Hamilton equation of an affine Hamiltonian h is equivalent with Euler-Lagrange equation of its dual Lagrangian L. Zerme… Show more

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Cited by 9 publications
(19 citation statements)
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“…In particular, according to the case of trivial foliation of M by points in [9], ν 1. (r−1) * F = ν r−1 F × M ν * F is denoted by ν r * M and play the role of the vectorial dual of the affine bundle ν r F → ν r−1 F .…”
Section: The Main Resultsmentioning
confidence: 99%
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“…In particular, according to the case of trivial foliation of M by points in [9], ν 1. (r−1) * F = ν r−1 F × M ν * F is denoted by ν r * M and play the role of the vectorial dual of the affine bundle ν r F → ν r−1 F .…”
Section: The Main Resultsmentioning
confidence: 99%
“…A transverse slashed lagrangian of order r is a map L r : ν r F → IR that is differentiable on an open subset ν r * F ⊂ν r F , where ν r F \ν r * F contains I r r−1 (ν r−1 F ). We denote by ν r ′ * F = π r r ′ (ν r * F ) ⊂ν r ′ F and we consider the slashed bundles ν * * F = ν * F \{0} and ν F → IR of the dual affine hamiltonian of L (see [9] for its classical definition and [11] for a coordinate description of the whole construction in the non-foliate case). Analogous, for 0 ≤ j < r − 1, we suppose, step by step, backward from r − 1 from 0, that there the usual partial derivatives of L (j+1) : ν j+1,(r−j−1) * * F = ν r−j−1 * F × M (ν * * F ) j+1 → IR in the highest order transverse coordinates (of order j + 1) define a well-defined Legendre map L (j+1) : ν j+1,(r−j−1) * *…”
Section: The Main Resultsmentioning
confidence: 99%
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