2008
DOI: 10.4153/cjm-2008-005-8
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Affine Lines on Affine Surfaces and the Makar–Limanov Invariant

Abstract: Abstract. A smooth affine surface X defined over the complex field C is an ML 0 surface if the MakarLimanov invariant ML(X) is trivial. In this paper we study the topology and geometry of ML 0 surfaces. Of particular interest is the question: Is every curve C in X which is isomorphic to the affine line a fiber component of an A 1 -fibration on X? We shall show that the answer is affirmative if the Picard number ρ(X) = 0, but negative in case ρ(X) ≥ 1. We shall also study the ascent and descent of the ML 0 prop… Show more

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Cited by 20 publications
(23 citation statements)
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“…(1) and (2): Let C 2 be as above the image of a general fiber C 1 of p 1 . By the (GSP), we know that C 2 is a smooth complete curve on V 2 , whence p a (C 2 ) = h. It follows from Theo-…”
Section: Lemma 12mentioning
confidence: 99%
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“…(1) and (2): Let C 2 be as above the image of a general fiber C 1 of p 1 . By the (GSP), we know that C 2 is a smooth complete curve on V 2 , whence p a (C 2 ) = h. It follows from Theo-…”
Section: Lemma 12mentioning
confidence: 99%
“…(3) Note thatX is an ML 1 -surface, or equivalently a smooth affine surface with a unique A 1 -fibration parametrized by an affine curve, if and only if so is X (see [1]). HenceX 2 has a unique A 1 -fibration over an affine curve.…”
Section: Proofmentioning
confidence: 99%
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“…Professor M. Miyanishi and the referees informed us that Theorem 1.1 and Corollary 1.2 were proved jointly by Gurjar, Masuda, Miyanishi and Russell [12].…”
Section: Introductionmentioning
confidence: 99%
“…In fact, if r = 1, then L as well as the boundary divisor ∞ − S − L is a linear chain. Hence X is an ML 0 -surface[7]. But the following argument works in the case r = 1 as well, provided the Gm-action stabilizes the component A since H 1 is a branching component of L + A.…”
mentioning
confidence: 99%