2001
DOI: 10.1006/jabr.2001.9021
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Affine Semi-linear Groups with Three Irreducible Character Degrees

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Cited by 6 publications
(3 citation statements)
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“…Working as in the proof of Theorem 3.1, we can define an action of F * and Gal(F ) on P . Applying Theorem 11 of [9], we can find subgroups K and N of F * Gal(F ) so that |K| = (p n − 1) ρ , |N | = m, cd(N K) = {1, n}, K is cyclic, N is nilpotent, and N K acts Frobeniusly on P . Take G = P N K. We now apply Lemma 2.1 to obtain the conclusion.…”
Section: Sketch Of Proofmentioning
confidence: 99%
“…Working as in the proof of Theorem 3.1, we can define an action of F * and Gal(F ) on P . Applying Theorem 11 of [9], we can find subgroups K and N of F * Gal(F ) so that |K| = (p n − 1) ρ , |N | = m, cd(N K) = {1, n}, K is cyclic, N is nilpotent, and N K acts Frobeniusly on P . Take G = P N K. We now apply Lemma 2.1 to obtain the conclusion.…”
Section: Sketch Of Proofmentioning
confidence: 99%
“…So let us consider the case p | (r − 1). Using [23,Lemma 8], we see that (r p c − 1) p = p c (r − 1) p if p > 2 or (r − 1) p > p and (r p c − 1) p = p c (r + 1) p otherwise. In any case, we always have (r…”
Section: Preliminariesmentioning
confidence: 99%
“…One year later, M. Isaacs proved that groups with 3 character degrees are solvable of derived length 3 (see [8] or [9,Theorem 12.15]). Several decades later, the structure of (solvable) groups with 3 character degrees was analyzed in detail in [22] (see also [18]). As the alternating group A 5 shows, it is not possible to prove that G is solvable when |cd(G)| = 4.…”
Section: Introductionmentioning
confidence: 99%