1986
DOI: 10.3367/ufnr.0150.198609l.0173
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Aleksei Aleksandrovich Naumov (Obituary)

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“…But there is no (multiplicative) identity operator in a Lie algebra, so this is also misleading in that context. Additionally, Ado's theorem [4][5][6] tells us that every Lie algebra has a finite-dimensional representation, and this will give a representative matrix for "I " which is certainly NOT the unit matrix. So, the right-hand side of (4) or (5) is just another element of h 1 , which we may call E. This implies that we should write the Heisenberg Lie algebra as…”
Section: Note On the Heisenberg Lie Algebramentioning
confidence: 99%
“…But there is no (multiplicative) identity operator in a Lie algebra, so this is also misleading in that context. Additionally, Ado's theorem [4][5][6] tells us that every Lie algebra has a finite-dimensional representation, and this will give a representative matrix for "I " which is certainly NOT the unit matrix. So, the right-hand side of (4) or (5) is just another element of h 1 , which we may call E. This implies that we should write the Heisenberg Lie algebra as…”
Section: Note On the Heisenberg Lie Algebramentioning
confidence: 99%