2014
DOI: 10.1016/j.jmaa.2014.04.043
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Alexandrov spaces with large volume growth

Abstract: Let (X, d) be an n-dimensional Alexandrov space whose Hausdorff measure H n satisfies a condition giving the metric measure space (X, d, H n ) a notion of having nonnegative Ricci curvature. We examine the influence of large volume growth on these spaces and generalize some classical arguments from Riemannian geometry showing that when the volume growth is sufficiently large, then (X, d, H n ) has finite topological type.

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Cited by 3 publications
(2 citation statements)
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“…Let us denote by Alex n [κ] the class of n-dimensional Alexandrov space of curvature ≥ κ. In [18] see Theorem 3.2, the authors prove the following Theorem 5.7. For an integer n ≥ 2, let (X, d) ∈ Alex n [−κ 2 ], κ ∈ R be a complete non-compact Alexandrov space whose Hausdorff measure H n satisfies the BG(0, n) condition.…”
Section: Geometry On Alexandrov Spacesmentioning
confidence: 99%
“…Let us denote by Alex n [κ] the class of n-dimensional Alexandrov space of curvature ≥ κ. In [18] see Theorem 3.2, the authors prove the following Theorem 5.7. For an integer n ≥ 2, let (X, d) ∈ Alex n [−κ 2 ], κ ∈ R be a complete non-compact Alexandrov space whose Hausdorff measure H n satisfies the BG(0, n) condition.…”
Section: Geometry On Alexandrov Spacesmentioning
confidence: 99%
“…For the case of Alexandrov spaces, the Abresch-Gromoll inequality [GM,M,ZZ2] and the Bishop-Gromov volume comparison inequality [LV,O,S2] still hold, the remain is to show that there exists δ = δ(n) > 0 such that if V ol(M ) ≥ ω n − δ then M is a topological manifold, which follows from (a) By Lemma 4.1(i), given any ǫ > 0, there exists δ = δ(ǫ, n) > 0 such that if V ol(M ) ≥ ω n − δ then V ol(Σ x ) ≥ ω n−1 − ǫ for any x ∈ M ;…”
Section: Proof Of the Theoremmentioning
confidence: 99%