1971
DOI: 10.1145/362919.362948
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Algorithm 415: Algorithm for the assignment problem (rectangular matrices)

Abstract: This algorithm is a companion to [3] where the theoretical background is described.

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Cited by 10 publications
(3 citation statements)
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“…However, the matrix WM(i, j) may not be square. Even though there are extensions of the Hungarian algorithm for rectangular matrices [7], the approach chosen here was to be padded the non-square matrices with dummy costs. The addition of dummy costs serves to penalize a query shape that has additional parts, especially if these additional parts are visually salient.…”
Section: Matching Parts and Shapesmentioning
confidence: 99%
“…However, the matrix WM(i, j) may not be square. Even though there are extensions of the Hungarian algorithm for rectangular matrices [7], the approach chosen here was to be padded the non-square matrices with dummy costs. The addition of dummy costs serves to penalize a query shape that has additional parts, especially if these additional parts are visually salient.…”
Section: Matching Parts and Shapesmentioning
confidence: 99%
“…The constraint in is due to the facts that each channel can be assigned to at most one group, and G ⩽ N. The problem in – is a standard assignment problem, and the optimal π * can be efficiently solved using the modified Munkres algorithm with a polynomial time of scriptO(G2N), which is much smaller than the complexity of the exhaustive search method scriptO(NMathClass-punc!MathClass-bin∕(N MathClass-bin−G)MathClass-punc!). Furthermore, it is easy to see that DMathClass-rel′(bold-italicλMathClass-punc,μ) MathClass-rel= bold1GT(bold-italicC MathClass-bin⊙bold-italicχ(πMathClass-bin*))bold1N.…”
Section: Joint Channel and Power Allocation For Outage Minimisation Imentioning
confidence: 99%
“…, / if channel n is assigned to group g. The constraint in (17) is due to the fact that each group can be assigned by one and only one channel. The constraint in (18) is due to the facts that each channel can be assigned to at most one group, and G 6 N. The problem in (16)-(18) is a standard assignment problem, and the optimal can be efficiently solved using the modified Munkres algorithm ‡ [25,26] with a polynomial time of O.G 2 N/, which is much smaller than the complexity of the exhaustive search method O.NŠ=.N G/Š/. Furthermore, it is easy to see that D 0 .…”
Section: Group Outage Probability Minimisationmentioning
confidence: 99%