“…Also since 2n < 2(2n − 2), we have sβ = (2n − 2)α and s < t. Now we consider each possibility for S, separately. If ρ(p, S) = {r i | i ∈ I} ∪ {p}, then using the results in [19], each r j ∈ π(S), where j ∈ I, is adjacent to p in Γ(S). Consequently, we get that β = 2α and m = n, that is S ∼ = L n (p 2α ).…”