2003
DOI: 10.1090/s0002-9939-03-06883-7
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An application of the Putnam-Fuglede theorem to normal products of self-adjoint operators

Abstract: Abstract. We prove that if we have two self-adjoint operators (bounded or not) and if their product is normal, then it is self-adjoint provided a certain condition is satisfied.

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Cited by 42 publications
(27 citation statements)
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“…Let Because as a nonnegative self-adjoint operator |B| satisfies the spectral condition that σ(|B|)) ∩ σ(−|B|) = {0} of Theorem 6 of [21], we know that |A||B| is normal iff it is self-adjoint.…”
Section: Now We Ask: What Can One Say Without Assuming Any Boundednes...mentioning
confidence: 99%
“…Let Because as a nonnegative self-adjoint operator |B| satisfies the spectral condition that σ(|B|)) ∩ σ(−|B|) = {0} of Theorem 6 of [21], we know that |A||B| is normal iff it is self-adjoint.…”
Section: Now We Ask: What Can One Say Without Assuming Any Boundednes...mentioning
confidence: 99%
“…A similar operator (in fact −i(|x| f ) ′ ) appeared in [19], in a different setting, where the reader may find more details. Then The following theorem generalizes the previous proposition to general densely defined A and B.…”
Section: Adjoint Of the Sum 21 The Hilbert Space Versionmentioning
confidence: 90%
“…In [18,Theorem 3] The study of operators satisfying Kaplansky theorem is of significant interest and is currently being done by a number of mathematicians around the world.Some developments toward this subject have been done in [6,10,12,15,16,17] and the references therein.…”
Section: A Densely Defined Operatormentioning
confidence: 99%