Aerospace Sciences Meeting 1964
DOI: 10.2514/6.1964-93
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Analysis of pendulum damper for satellite wobble damping

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Cited by 5 publications
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“…2d, positions of pendulums 1-3). There are three essentially different equilibrium positions of the pendulums on the lower plane: k k 1 Combining these positions, we obtain nine essentially different steady motions.…”
Section: Restrictions Of the Problemmentioning
confidence: 99%
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“…2d, positions of pendulums 1-3). There are three essentially different equilibrium positions of the pendulums on the lower plane: k k 1 Combining these positions, we obtain nine essentially different steady motions.…”
Section: Restrictions Of the Problemmentioning
confidence: 99%
“…Attitude stabilization of the rotational axis of a carrying perfectly rigid body (PRB) is an important problem of mechanics. Such bodies can be artificial satellites or spacecraft with spin stabilization [1][2][3][4][5][6][7][8][9][10][11][12][13][14]. Spin stabilization is disadvantageous in that, for example, inaccurate initial rotation imparted to a symmetric satellite causes its rotational axis to long precess about a fixed axis (axis of precession).…”
mentioning
confidence: 99%
“…(7). The apparent spring constant of the damper is diminished by the centrifugal force due to spin about the z axis (the co 2 2 term) and also by the contribution of the cross spin centrifugal force (the co y 2 term). Although the latter term may be small compared to the first terms, it cannot be neglected, since this periodic force can cause parametric excitation of the damper mass motion.…”
Section: Substituting Into Euler's Equationsmentioning
confidence: 99%
“…Finally, let the spring (and hence A) be undefprmed when P lies on G 2 and choose 6, the distance between L and G*, m p , the mass of P, m G , the mass of G, and 7 7 , 7 2 , I 3 , the moments of inertia of G about G/, G 2 , G 3 , in such a way that where /* is defined as A I 2 =I 3 +pb 2 =J 2 p +m G ) (7) (8) If these requirements are fulfilled, it is guaranteed that when A is undeformed, the central inertia ellipsoid of S is a spheroid whose axis is parallel to g lt the moment of inertia of S about the line passing through S* and parallel to gj is equal to /;, and the moment of inertia of S about any line passing through S* and perpendicular to gj is equal to J 2 . Fur- thermore, the angular momentum of S relative to S* is then given, for all /, by H=H lg] +H 2 g 2 +H 3 g 3 provided H lt H 2 , H 3 be defined as (9) (10) (11) (12) where q is the distance from P to G 2 (see Fig. 4) and (f ) i = N u R .…”
Section: Tt)mentioning
confidence: 99%