2019
DOI: 10.14708/ma.v47i1.6497
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Analysis of the AOK Plus data and derived hospital network

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Cited by 5 publications
(7 citation statements)
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“…To provide further information about the data, we showed also the distribution of LOS in S2 – S4 Figs, of hospitalizations in S5 Fig , of network weights in S6 Fig , of in- and out-degrees of each hospital in S7 and S8 Figs, and of in- and out-strengths in S9 and S10 Figs. More detailed information about the AOK data can be also accessed in our previous work [ 23 , 24 ].…”
Section: Resultsmentioning
confidence: 99%
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“…To provide further information about the data, we showed also the distribution of LOS in S2 – S4 Figs, of hospitalizations in S5 Fig , of network weights in S6 Fig , of in- and out-degrees of each hospital in S7 and S8 Figs, and of in- and out-strengths in S9 and S10 Figs. More detailed information about the AOK data can be also accessed in our previous work [ 23 , 24 ].…”
Section: Resultsmentioning
confidence: 99%
“…We also excluded all hospitals located outside the respective federal state as they did not have the same local coverage of the studied population in their catchment area. The datasets contained various types of overlaps, which suggested that a patient stayed in multiple hospitals on a given day [ 23 , 24 ]. Overlaps can happen due to several factors.…”
Section: Methodsmentioning
confidence: 99%
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“…In case of the network derived from the provided data, the regularity of matrix A was checked numerically by empirical verification ( A 5 has positive elements only), but this result is dependent on numerical errors. Nevertheless, we can use a lemma providing an analytical argument, for details see [ 14 ] or S1 Appendix . A non-zero pattern of matrix A is presented in Fig 5b .…”
Section: Methodsmentioning
confidence: 99%
“…Figure 6: (a) In-degree and out-degree for each hospital node of the network (self-loops not included); (b) out-degree for each community node of the network (self-loops not included), in-degree for all community nodes are equal to 1. the regularity of matrix A was checked numerically by empirical verification (A 5 has positive elements only), but this result is dependent on numerical errors. Nevertheless, we can use a lemma providing an analytical argument, for details see [14] or Appendix 5. A non-zero pattern of matrix A is presented in Figure 5.…”
Section: 4)mentioning
confidence: 99%