2013
DOI: 10.1088/0951-7715/26/12/3231
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Analytic expanding circle maps with explicit spectra

Abstract: Abstract. We show that for any λ ∈ C with |λ| < 1 there exists an analytic expanding circle map such that the eigenvalues of the associated transfer operator (acting on holomorphic functions) are precisely the nonnegative powers of λ and λ. As a consequence we obtain a counterexample to a variant of a conjecture of Mayer on the reality of spectra of transfer operators.

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Cited by 23 publications
(26 citation statements)
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“…The spectrum of a Koopman operator depends on the dynamics of the underlying map and can be computed analytically, for example, for maps with a unique (attractive) fixed point, as mentioned before, and for purely expanding circle maps [35]. In our case of invertible access maps there are only two possible types of dynamics, which determine our delay types, conservative and dissipative delay.…”
Section: Discussionmentioning
confidence: 99%
“…The spectrum of a Koopman operator depends on the dynamics of the underlying map and can be computed analytically, for example, for maps with a unique (attractive) fixed point, as mentioned before, and for purely expanding circle maps [35]. In our case of invertible access maps there are only two possible types of dynamics, which determine our delay types, conservative and dissipative delay.…”
Section: Discussionmentioning
confidence: 99%
“…As we shall see presently, the above choices of the annuli guarantee that L is a well-defined linear operator which maps H 2 (A) compactly to itself. In order to show this, we shall employ a factorization argument, similar to the ones used in [4,21]. Let H ∞ (A ′ ) be the Banach space of bounded holomorphic functions on A ′ equipped with the supremum norm.…”
Section: Circle Maps and Transfer Operatorsmentioning
confidence: 99%
“…Example 5.7. For the family of maps B(z) = z(µ − z)/(1 − µz) considered in [21], the restriction B| T is an expanding circle map for any µ ∈ D. The attracting fixed points are z 0 = 0 andẑ 0 = ∞ with λ(z 0 ) = µ and λ(ẑ 0 ) = µ. Thus σ(L) = {µ n : n ∈ N 0 } ∪ {µ n : n ∈ N} ∪ {0} .…”
Section: Spectrum For Blaschke Productsmentioning
confidence: 99%
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“…More recently, Bandtlow et. al [2,20] calculated the resonances of real analytic expanding maps T : S → S on the unit circle S explicitly for Blaschke products. Their transfer operator acts on the Hardy space of holomorphic functions on the annulus.…”
Section: Introductionmentioning
confidence: 99%