“…Then D ( T 0, m ) is given by Dfalse(T0,mfalse):={f∈X0,m:rf∈AC(double-struckR+), ddx(rf),qf∈X0,m and r(x)f(x)→0 as x→0+}. To make the Hille–Yosida theorem applicable, we must determine the resolvent operator, R (λ, T 0, m ). Following [1, Section 5.2], we begin by solving λffalse(xfalse)+ddxfalse(rfalse(xfalse)ffalse(xfalse)false)+qfalse(xfalse)ffalse(xfalse)=gfalse(xfalse),1emx∈double-struckR+, where g ∈ X 0, m . On introducing antiderivatives of 1/ r and q / r , respectively, defined on double-struckR+ by Rfalse(xfalse):=∫1x1rfalse(sfalse)…”