1991
DOI: 10.1103/physrevd.44.1962
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Analyzing power in pion-proton bremsstrahlung, and theΔ++(1232)magnetic moment

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Cited by 87 publications
(83 citation statements)
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“…The value for the ∆ ++ is extracted from radiative pion-nucleon scattering (π + p −→ π + pγ) [9,[598][599][600], and that for the ∆ + from radiative photoproduction of neutral pions (γp −→ π 0 pγ ) [601]. Information on the ∆ 0 and ∆ − magnetic moments and all other electromagnetic properties of the ∆ isomultiplet is totally missing.…”
Section: Delta Electromagnetic Form Factorsmentioning
confidence: 99%
“…The value for the ∆ ++ is extracted from radiative pion-nucleon scattering (π + p −→ π + pγ) [9,[598][599][600], and that for the ∆ + from radiative photoproduction of neutral pions (γp −→ π 0 pγ ) [601]. Information on the ∆ 0 and ∆ − magnetic moments and all other electromagnetic properties of the ∆ isomultiplet is totally missing.…”
Section: Delta Electromagnetic Form Factorsmentioning
confidence: 99%
“…The effective Lagrangian of the ∆(1232) resonance 1 µ N denotes the nuclear magneton e/(2m p ). 2 Here, p stands for small parameters of the theory like the pion mass and the ∆-nucleon mass difference.…”
Section: Effective Lagrangianmentioning
confidence: 99%
“…The magnetic moment of the ∆ ++ (1232) has been investigated experimentally by measuring the π + p bremsstrahlung reaction [1,2] which has been analyzed within various theoretical frameworks [3,4,5,6,7]. The Particle Data Group only makes a rough estimate of the range the moment is expected to lie within, µ ∆ ++ = (3.7 − 7.5) µ N [8], 1 while SU(6) symmetry predicts for a member of the decuplet with charge eQ the value µ = Qµ p (µ p : proton magnetic moment) [9], resulting for the ∆ ++ in µ ∆ ++ = 5.58 µ N .…”
Section: Introductionmentioning
confidence: 99%
“…For the ∆ ++ (1232), it was therefore proposed to measure its MDM through the π + p → γπ + p reaction [14], and two experiments were performed [15,16]. Using different theoretical analyses, the Particle Data Group (PDG) [17] quotes as range of the MDM : µ ∆ ++ = 3.7 − 7.5 µ N , where µ N is the nuclear magneton.…”
Section: Introductionmentioning
confidence: 99%